A load cell datasheet will typically specify an excitation voltage, for example 10 Volts. This implies that you need to run the device at 10V, but that is not the case. It is the ratio of the input voltage to the output voltage that is all-important, and you can use the load cell at lower excitation voltages if that works better with your design constraints (provided the signal-to-noise ratio is acceptable).
Heating
Increased voltage = increased heating of the strain gauge. For some applications this might mean that a lower excitation voltage is preferred. For applications where continuous fast measurements are not needed, the bridge can be turned off when not measuring to reduce heating.
Noise
If you increase the excitation voltage by a factor of three, the output signal (the voltage across the bridge) will increases by a factor of three. If the noise present is constant, then the signal to noise ratio decreases three-fold when you increase the excitation voltage by three.
This means that using a higher excitation voltage, e.g. 10V if that is what a load cell is specified to use, will be better from a noise point of view than, say, 3.3V. However, filtering noise with integration and/or analog low pass filtering, for example, can result in the noise being kept to an acceptable level even with a low 3.3V excitation voltage. It depends on the specifics of your application as there can be situations where noise is a significant source of error and a higher excitation voltage is favorable.
High excitation voltages
You have a load cell that is specified for a +15V excitation voltage and you have a 24V power supply, so you want to give it the full 15V excitation voltage. That’s great from a signal-to-noise ratio point of view, you’ll get a higher voltage range output from the load cell, BUT remember that its differential voltage output will be centered at (excitation voltage / 2), so 7.5V in this case. Can your amplifier IC accept that voltage on its analog input pin? If not you’ll need to look at a low noise bipolar supply to the load cell instead, or offsetting the 0V and VCC rail provided to your amplifier IC.